Hello Skill L,
You have two bullets next to each other in a 6-barrel gun. This means there is a series of 4 chambers containing no bullets. You pull the trigger once. Nothing happens. This means that you pulled the trigger on one of the 4 empty chambers. Since the cylinder rotates only one chamber, the ONLY one of these 4 where a bullet could have rotated to the firing position is the one directly adjacent to the two bullets. If the first pull of the trigger was on any of the 3 other empty chambers, another empty chamber must rotate to the firing position - you survive.
If you re-spin the chambers, your chance is only 66.66%, since you have once again randomised the firing chamber - the chances of surviving are 4 in 6 (4 empty chambers, 2 bullets).
Spot on.
There is therefore a 3 in 4 chance that you will survive if you pull the trigger again - 75%.
I think this is wrong. Yes there are 3 safe empties out of 4, but you have
already selected one of them on your first pull, so you must refer to the probability applicable to that pull, namely 1/6 (as the game starts with a random spin).
To put it another way, the second pull doesn't randomly select one of the four empty chambers, it selects the next chamber, so what is important is the odds of selecting the only chamber before the first bullet on the first spin.
As this is 1/6, I think you're twice as likely to live if you pull again.
But (and this is what I find interesting about the problem):
You are handed a revolver, with two bullets placed in adjacent chambers in the 6-chamber cylinder. The cylinder is spun to a random position and the loaded gun is handed to you. You put the barrel to your head and pull the trigger - an empty click.
My answer supposes that the first spin and pull could have resulted in death (although on this occasion it hasn't). As the question clearly states "the cylinder is spun to a random position", it is a fair expectation.
But if the problem-setter insists this can't happen (i.e. the first spin is actually not random, because it
always lands on an empty chamber) then I defer to your and others' answer of 1/4, albeit with a complaint that the question is now self-contradictory.