hi iam using robot for trading
i would like to know the the trade size mathematic formula to hold a position down to 40 pip loss for usdjpy
stop out 50%
leverage 500
i thinks its like that
i have calculate this 40 pip of loss=400$ for usdjpy
for a balance of 600$
leverage 500
stop out 50%
so i think its 600$(balance)-400$(40 pip of sl)=200$
(600*105.331*500)/(105.331*100000)= 3 Lots
(400*105.331*500)/(105.331*100000)= 2 lots
so i think its 3 lots -2 lots= 1 lot of trading size to hold down to 40 pip of loss
but the suporrt of my broker say this
please try to understand, the maximum you can place 2 lots. and if you want to place 1 lot then your calculation is perfect.
so iam little confused
thanks for enlighten me
i would like to know the the trade size mathematic formula to hold a position down to 40 pip loss for usdjpy
stop out 50%
leverage 500
i thinks its like that
i have calculate this 40 pip of loss=400$ for usdjpy
for a balance of 600$
leverage 500
stop out 50%
so i think its 600$(balance)-400$(40 pip of sl)=200$
(600*105.331*500)/(105.331*100000)= 3 Lots
(400*105.331*500)/(105.331*100000)= 2 lots
so i think its 3 lots -2 lots= 1 lot of trading size to hold down to 40 pip of loss
but the suporrt of my broker say this
please try to understand, the maximum you can place 2 lots. and if you want to place 1 lot then your calculation is perfect.
so iam little confused
thanks for enlighten me