new_trader
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Might be good to have a seperate thread:
Post your answer here and a link to it in the Puzzle thread
Post your answer here and a link to it in the Puzzle thread
Might be good to have a seperate thread:
Post your answer here and a link to it in the Puzzle thread
The question you ask one of the men is:
"If I were to ask the other man which door goes to heaven, which door would he pick?"
Go through the other door.
Here's my answer to the hourglass one.........not sure if it's cheating and probably wrong anyway since there would be no way to do it "perfectly" so to speak.
1: Mark a line at the sand height on the 4 minute hourglass when the sand is all in the bottom.
2: Open the hourglass and tip out the sand.
3: Open the 7 minute one and pour 4 mins worth of sand into 4 min glass.
4: You are left with 3 mins worth of sand in 7 min glass.
5: Tip 7 min glass over and allow sand to run to bottom.
6: Repeat step 5
7: Repeat step 5
Cheers,
PKFFW
P.S: if it's wrong I will continue to work on it
Small error in (2), you have to let 7 running instead of turning over.I have not looked at the answer:
2) When 4 runs out, turn 4 & 7 over again (Total time elapsed is 4 min at this point. The 4 has 0 min remaining and the 7 has 3 min remaining)
That's right, good one!I think you are on the right track N_T but I think you just didn't write it down right. At least that or I'm reading your answer wrong. If you flip both back over in your step 2 the 7 min glass will now have 4 mins in the top to run as 4 mins will have fallen to the bottom while the 4 min glass was running out.
Small error in (2), you have to let 7 running instead of turning over.
That's right, good one!
http://www.trade2win.com/boards/foyer/22827-puzzles-18.html#post427148
I'm convinced it has something to do with the way the pieces are redrawn. I am going to try and solve it at work using autocad on Sunday...too lazy to try on paper.![]()
http://www.trade2win.com/boards/foyer/22827-puzzles-18.html#post427148
I'm convinced it has something to do with the way the pieces are redrawn. I am going to try and solve it at work using autocad on Sunday...too lazy to try on paper.![]()
its a weird one!
the orange block = 7 squares
light green block = 8 squares
green triangle = 5 squares ( (5 x 2) / 2)
red triangle = 12 squares ( (8 x 3) / 2)
total surface area = 7 + 8 + 5 + 12 = 32 squares
big triangle = 32.5!!! ( (13 x 5) / 2)
I dont understand how the big triangle surface area is 0.5 square bigger than the smaller pieces added together.
Am I making false assumptions about the surface area of the triangles? (Length x Height / 2) ??